Random Point in Non-Overlapping Rectangles
LeetCode August - Day 22
Problem Statement
Given a list of non-overlapping axis-aligned rectangles rects, write a function pick which randomly and uniformily picks an integer point in the space covered by the rectangles.
Note:
- An integer point is a point that has integer coordinates. A point on the perimeter of a rectangle is included in the space covered by the rectangles.
- ith rectangle = rects[i] = [x1,y1,x2,y2], where [x1, y1] are the integer coordinates of the bottom-left corner, and [x2, y2] are the integer coordinates of the top-right corner.
- length and width of each rectangle does not exceed 2000.
- 1 <= rects.length <= 100
- pick returns a point as an array of integer coordinates [p_x, p_y]
- pick is called at most 10000 times.
Example 1:
Input:
["Solution","pick","pick","pick"]
[[[[1,1,5,5]]],[],[],[]]
Output:
[null,[4,1],[4,1],[3,3]]
Example 2:
Input:
["Solution","pick","pick","pick","pick","pick"]
[[[[-2,-2,-1,-1],[1,0,3,0]]],[],[],[],[],[]]
Output:
[null,[-1,-2],[2,0],[-2,-1],[3,0],[-2,-2]]
Explanation of Input Syntax:
The input is two lists: the subroutines called and their arguments. Solution’s constructor has one argument, the array of rectangles rects. pick has no arguments. Arguments are always wrapped with a list, even if there aren’t any.
Inputs, Outputs, Constraints & Exceptions
- I: number[][]
- O: number[]
- C: none/optimise
- E: - area of one of the rects is 0
- area of all rects is 0
Code
class Solution:
def __init__(self, rects: List[List[int]]):
self.rects = rects
self.weights = []
self.sum = 0
for x1, y1, x2, y2 in rects:
area = (x2 - x1 + 1) * (y2 - y1 + 1)
self.weights.append(area)
self.sum += area
self.weights = [x / self.sum for x in self.weights]
def pick(self) -> List[int]:
rect = random.choices(population = self.rects, weights = self.weights, k = 1)[0]
x1, y1, x2, y2 = rect
return [random.randint(x1,x2), random.randint(y1,y2)]